Tourist Information

General Information

Demographic Information

Arvada is a census-designated place (CDP), situated in Sheridan County, Wyoming, United States. The population was 33 at the 2000 census. Arvada is located at 44°39′15″N, 106°7′52″W (44.654207, -106.131238) at 3671 feet above the see level. According to the United States Census Bureau, the Arvada CDP has a total area of 2.1 square miles (5.5 km²). As of the census of 2000, there were 33 people, 18 households, and 9 families residing in the CDP. The population density was 15.4 people per square mile (6.0/km²). There were 26 housing units at an average density of 12.1/sq mi (4.7/km²).